class Solution:
# @param A, a list of integers
# @param target, an integer to be searched
# @return an integer
def search(self, A, target):
n=len(A)
if n==0:
return -1
left=0
right=n-1
while left<=right:
mid=(left+right)//2
if left==right:
return left if target==A[left] else -1
elif target==A[mid]:
return mid
elif A[left]<=A[mid]:
if A[left]<=target<A[mid]:
right=mid-1
else:
left=mid+1
else:
if A[mid]<target<=A[right]:
left=mid+1
else:
right=mid-1
return -1
Tuesday, September 9, 2014
Leetcode: Search in Rotated Sorted Array @Python
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