class Solution:
# @return a float
def getMedian(self, A, B, k):
# return kth smallest number of arrays A and B, assume len(A) <= len(B)
lenA = len(A); lenB = len(B)
if lenA > lenB: return self.getMedian(B, A, k)
if lenA == 0: return B[k-1]
if k == 1: return min(A[0], B[0])
pa = min(k/2, lenA); pb = k - pa
return self.getMedian(A[pa:], B, k - pa) if A[pa - 1] <= B[pb - 1] else self.getMedian(A, B[pb:], k - pb)
def findMedianSortedArrays(self, A, B):
lenA = len(A); lenB = len(B)
if (lenA + lenB) % 2 == 1:
return self.getMedian(A, B, (lenA + lenB) / 2 + 1)
else:
return 0.5 * ( self.getMedian(A, B, (lenA + lenB) / 2) + self.getMedian(A, B, (lenA + lenB) / 2 + 1) )
Friday, September 19, 2014
Leetcode: Median of Two Sorted Arrays @Python
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